Rationalizing the denominator means eliminating any radical expressions in the denominator such as square roots and cube roots.
Key Idea :
Multiply both the numerator and denominator of the given fraction by an appropriate value, such that after simplification, the denominator no longer contains radicals.
When you have a binomial with radical term like (x + √y) in denominator, multiply both numerator and denominator by the conjugate of (x + √y), that is (x - √y).
Rationalize the denominator in the following examples.
Example 1 :
¹⁄√ₓ
Solution :
= ¹⁄√ₓ
Multiply both the numerator and denominator by √x.
= (1 ⋅ √x)/(√x ⋅ √x)
= √x/x
Example 2 :
¹⁄₍ₓ ₊ √y₎
Solution :
= ¹⁄₍ₓ ₊ √y₎
Multiply both numerator and denominator by (x - √y).
= [1 ⋅ (x - √y)] / [(x + √y)(x - √y)]
Use the algebraic identity a2 - b2 = (a + b)(a - b) in denominator to simplify.
= (x - √y) / [x2 - (√y)2]
= (x - √y) / (x2 - y)
Example 3 :
⁽√ˣ ⁺ √ʸ⁾⁄√x
Solution :
= ⁽√ˣ ⁺ √ʸ⁾⁄√x
Multiply both the numerator and denominator by √x.
= (√x + √y)√x / (√x ⋅ √x)
Distribute and simplify.
= [(√x ⋅ √x) + (√y ⋅ √x)] / x
= [x + √(xy)]/x
Example 4 :
(√x + √y)/(√x - √y)
Solution :
= (√x + √y)/(√x - √y)
Multiply both numerator and denominator by (x + √y).
= [(√x + √y)(√x + √y)] / [(√x - √y)(√x + √y)]
= (√x + √y)2 / [(√x)2 - (√y)2]
= [(√x)2 + 2√x√y + (√y)2] / (x - y)
= (x + 2√(xy) + y) / (x - y)
Example 5 :
√(100x/11y)
Solution :
= √(100x/11y)
Distribute the radical to numerator and denominator.
= √(100x)/√(11y)
So, multiply both numerator and denominator by the 11y.
= [√(100x) ⋅ √(11y)] / √(11y) ⋅ √(11y)]
Simplify.
= √(100x ⋅ 11y) / 11y
100 is a perfect square and √100 = 10.
= 10√(11xy) / 11y
Example 6 :
Find the value of ab.
1/(x + y√3)
Solution :
= 1/(x + y√3)
Multiply both numerator and denominator by (x - y√3).
= [1 ⋅ (x - y√3)] / [(x + y√3)(x - y√3)]
Use the algebraic identity a2 - b2 = (a + b)(a - b) in denominator to simplify.
= (x - y√3) / [x2 - (y√3)2]
= (x - y√3) / [x2 + y2(√3)2]
= (x - y√3) / (x2 + 3y2)
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