To find questions from 1 to 4, please visit the page "Practice Worksheet Relations and Functions with Answers"
Question 5 :
Find the domain of the function f(x) =
Solution :
Let t = √(1 - √(1 - x2))
f(x) = √(1 - t)
1 - t ≥ 0
t ≤ 1
By applying the value of t, we get
√(1 - √(1 - x2)) ≤ 1
1 - √(1 - x2)) ≤ 1
Subtracting 1 through out the equation,
- √(1 - x2)) ≤ 0
√(1 - x2)) ≥0
Taking squares on both sides,
(1 - x2) ≥ 0
- x2 ≥ -1
x ≤ 1
Hence the domain is x ∈ [-1, 1]
Question 6 :
If f (x) = x2 , g(x) = 3x and h(x) = x −2 , Prove that (f ∘ g) ∘ h = f ∘ (g ∘ h) .
Solution :
L.H.S :
(f ∘ g) ∘ h
(f ∘ g) = f[g(x)]
(f ∘ g) = f[3x]
Now we have to apply 3x as x in the function f(x)
f(3x) = (3x)2
f(3x) = 9x2
(f ∘ g) ∘ h = (f ∘ g) [h(x)]
= (f ∘ g) [x - 2]
Now we have to apply x - 2 as x in the function (f ∘ g)
= 9(x - 2)2
= 9(x2 - 4x + 4)
= 9x2 - 36x + 36 ---------(1)
R.H.S :
f ∘ (g ∘ h)
(g ∘ h) = g[h(x)]
(g ∘ h) = g[x - 2]
Now we have to apply x - 2 as x in the function g(x)
g(x - 2) = 3(x - 2)
(g ∘ h) = 3x - 6
f ∘ (g ∘ h) = f [3x - 6]
Now we have to apply 3x - 6 as x in the function f(x)
= (3x - 6)2
= 9x2 - 36x + 36 ---------(2)
Hence proved.
Question 7 :
Let A = {1, 2} and B = {1, 2, 3, 4} , C = {5, 6} and D = {5, 6 ,7, 8} . Verify whether A × C is a subset of B × D?
Solution :
A = {1, 2} and C = {5, 6}
A x C = {(1, 5) (1, 6) (2, 5) (2, 6)} ----(1)
B = {1, 2, 3, 4} and D = {5, 6 ,7, 8}
B x D = { (1, 5) (1, 6) (1, 7) (1, 8) (2, 5) (2, 6) (2, 7) (2, 8) (3, 5) (3, 6) (3, 7) (3, 8) (4, 5) (4, 6) (4, 7) (4, 8) }
Hence A x C is the subset of B x D.
Question 8 :
If f(x) = (x - 1)/(x + 1), x ≠ 1 show that f(f(x)) = -1/x, provided x ≠ 0
Solution :
f(x) = (x - 1)/(x + 1) (Given)
f(f(x)) =
Hence proved.
Question 9 :
If the universal set E = {x : x is a positive integer < 25}, A = {2, 6, 8, 14, 22}, B = {4, 8, 10, 14} Prove that (A n B)' = A' U B'
Solution :
E = {1, 2, 3, 4, 5, ............ 25}, A = {2, 6, 8, 14, 22}, B = {4, 8, 10, 14}
A n B = {8, 14}
(A n B)' = {1, 2, 3, 4, 5, 6, 7, 9, 10, 11, 12, 13, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25} -----(1)
A' = {1, 3, 4, 5, 7, 9, 10, 11, 12, 13, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25}
B' = {1, 2, 3, 5, 6, 7, 9, 11, 12, 13, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25}
A'UB' = {1, 2, 3, 4, 5, 6, 7, 9, 10, 11, 12, 13, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25} -----(2)
(1) = (2)
Hence it is proved.
Question 10 :
A survey shows that 74% of the Indian like grapes, whereas 68% like bananas. What percentage of the Indian like both grapes and bananas if everybody likes wither fruit ?
a) 42% b) 26% c) 58% d) 62%
Solution :
Let A be grapes and B be banana
Total number of people surveyed = 100
n(A) = 74
n(B) = 68
Let x be the number of people who likes both Grapes and Bananas.
n(AnB) = x
n(AuB) = n(A) + n(B) - n(AnB)
100 = 74 + 68 - x
100 = 142 - x
x = 142 - 100
x = 42
So, 42% of people who likes both grapes and bananas.
Question 11 :
If f(x) : N->R is a function defined as f(x) = 4x + 3 for all x belongs to N, the f-1(x) is
Solution :
f(x) = 4x + 3
Let y = 4x + 3
Solve for x,
y - 3 = 4x
x = (y - 3) / 4
Replace x by f-1(x) and y by x.
f-1(x) = (x - 3) / 4
Question 12 :
The number of subsets of the set {0, 1, 2, 3} is
Solution :
Let A = {0, 1, 2, 3}
Number of elements in the set A, that is n(A) = 4
Number of subsets = 2n
= 24
= 16
So, the number of subsets of the set A is 16.
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