SIMPLIFYING SQUARE ROOTS AND CUBE ROOTS WORKSHEET

(1)  √289

(2)  √441

(3)  √625

(4)  √1024

(5)  √0

(6)  √1369

(7)  √6889

(8)  √10000

(9)   3√1

(10)  3√64

(11)  3√125

(12)  3√343

(13)  4√0

(14)   4√16

(15)  3√-1

(16)  3√-27

(17)  4√625

(18)  5√1

(19)  5√-1

(20)  5√-32

Find :

Problem 1 :

√289

Solution :

Given, √289

We use prime factorization to find square roots.

we get,

√289  =  √(17 × 17)

For every two same values, we can take one out of them.

=  17

So, the answer is 17

Problem 2 :

√441

Solution :

Given, √441

We use prime factorization to find square roots.

We get,

√441  =  √(3 × 3 × 7 × 7)

For every two same values, we can take one out of them.

=  3 × 7

=  21

So, the answer is 21

Problem 3 :

√625

Solution :

Given, √625

We use prime factorization to find square roots.

We get,

√625  =  √(5 × 5 × 5 × 5)

For every two same values, we can take one out of them.

=  5 × 5

=  25

So, the answer is 25

Problem 4 :

√1024

Solution :

Given, √1024

We use prime factorization to find square roots.

We get,

√1024  =  √(2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2)

For every two same values, we can take one out of them.

=  2 × 2 × 2 × 2 × 2

=  32

So, the answer is 32

Problem 5 :

√0

Solution :

Given, √0

√0  =  √0 x 0

Since, square root of zero is zero

So, the answer is 0.

Problem 6 :

√1369

Solution :

Given, √1369

We use prime factorization to find square roots.

We get,

So, the answer is 37

Problem 7 :

√6889

Solution :

Given, √6889

We use prime factorization to find square roots.

We get,

√6889  =  √(83 × 83)

=  83

So, the answer is 83

Problem 8 :

√10000

Solution :

Given, √6889

We use prime factorization to find square roots.

We get,

√10000  =  √(5 × 5 × 5 × 5 × 2 × 2 × 2 × 2)

=  5 × 5 × 2 × 2

=  100

So, the answer is 100.

Problem 9 :

 3√1

Solution :

Given, 3√1

3√1  =  3√(1 x 1 x 1)  ==>  1

So, the answer is 1

Problem 10 :

3√64

Solution :

Given, 3√64

We use prime factorization to find cube roots.

We get,

3√(2 × 2 × 2 × 2 × 2 × 2)

=  2 × 2

=  4

So, the answer is 4

Problem 11 :

3√125

Solution :

Given, 3√125

We use prime factorization to find cube roots.

We get,

3√(5 × 5 × 5)

For every three same values, we can take one out of them.

=  5

So, the answer is 5

Problem 12 :

3√343

Solution :

Given, 3√343

We use prime factorization to find cube roots.

We get,

3√(7 × 7 × 7)

=  7

So, the answer is 7

Problem 13 :

4√0

Solution :

Given, 4√0

Since fourth root of 0 is 0

So, the answer is 0

Problem 14 :

4√16

Solution :

Given, 4√16

We use prime factorization to find fourth roots.

We get,

4√(2 × 2 × 2 × 2)

For every four same values, we can take one out of them.

=  2

So, the answer is 2

Problem 15 :

3√-1

Solution :

Given, 3√-1

Since cube root of - 1 is - 1

So, the answer is – 1

Problem 16 :

3√-27

Solution :

Given, 3√-27

We use prime factorization to find cube roots.

We get,

3√(-3) × (-3) × (-3)

=  -3

So, the answer is - 3

Problem 17 :

4√625

Solution :

Given, 4√625

We use prime factorization to find fourth roots.

We get,

4√(5 × 5 × 5 × 5)

=  5

So, the answer is 5

Problem 18 :

5√1

Solution :

Given, 5√1

Since fifth root of 1 is 1

So, the answer is 1

Problem 19 :

5√-1

Solution :

Given, 5√-1

5√-1  =  5√(-1) x (-1) x (-1) x (-1) x (-1)

So, the answer is – 1

Problem 20 :

5√-32

Solution :

Given, 5√-32

We use prime factorization to find fifth roots.

We get,

5√(-2) × (-2) × (-2) × (-2) × (-2)

=  -2

So, the answer is -2

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