If the length, breadth and height of a cuboid are l, b and h respectively.
Then
(i) Total Surface Area = 2 (lb + bh + lh ) sq.units.
(ii) Lateral Surface Area = 2 (l+b)h sq.units
(iii) Volume = l b h
Problem 1 :
Find the volume of a cuboid whose dimensions are
(i) length = 12 cm, breadth = 8 cm, height = 6 cm
(ii) length = 60 m, breadth = 25 m, height = 1.5 m
Solution :
(i) length = 12 cm, breadth = 8 cm, height = 6 cm
Volume of cuboid = l b h
= 12 (8) (6)
= 12 (48)
= 576 cm3
(ii) length = 60 m, breadth = 25 m, height = 1.5 m
Volume of cuboid = l b h
= 60 (25) (1.5)
= 60 (37.5)
= 2250 cm3
Problem 2 :
The dimensions of a match box are 6 cm × 3.5 cm × 2.5 cm. Find the volume of a packet containing 12 such match boxes.
Solution :
length = 6 cm, breadth = 3.5 cm and height = 2.5 cm
Volume of cuboid = lbh
= 6 (3.5) (2.5)
= 52.5 cm3
Volume of 12 boxes = 52.5 (12)
= 630 cm3
Problem 3 :
The length, breadth and height of a chocolate box are in the ratio 5 : 4 : 3. If its volume is 7500 cm3, then find its dimensions.
Solution :
Volume of box = 7500 cm3
Let 5x, 4x and 3x be the length breadth and height of chocolate boxes respectively.
5x (4x) (3x) = 7500
60x3 = 7500
x3 = 125
x = 5 cm
length = 5(5) = 25 cm
breadth = 4(5) = 20 cm
height = 3(5) = 15 cm
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