Problem 1 :
Solve for x :
5 + x > 3
Problem 2 :
Solve for p :
p - 7 < 3
Problem 3 :
Solve for r :
2r ≤ 6
Problem 4 :
Solve for m :
(1/4)m ≤ 3
Problem 5 :
Solve for p :
8 - p ≥ 12
Problem 6 :
Solve for m :
m - 10 < -15
Problem 7 :
Solve for v :
v + 5/3 > -1/3
Problem 8 :
Solve for m :
38 - m ≤ -44
Problem 9 :
Solve for m :
-11m > 22
Problem 10 :
Solve for v :
-25.7 - v < -40.3
Problem 11 :
When 7 is added to a number, we get the result greater than 25. Find the number.
Problem 12 :
When we multiply a number by 4, we get the result less than 124. Find the number.
Problem 13 :
When we divide a number by 7, we get the result greater than 14. Find the number.
Problem 14 :
John had some candies. He gave 5 candies to his friend and now he has more than 18 candies. How many candies did John initially have ?
Problem 15 :
Alex borrowed some money from Jose. After 3 years, Alex returned more than 2 times of borrowed money to Jose. If the returned money is $226, how much money did Alex borrow from Jose ?
Problem 1 :
Solve for x :
5 + x > 3
Solution :
5 + x > 3
Subtract 5 from each side.
So, the value of x is greater than -2.
Problem 2 :
Solve for p :
p - 7 < 3
Solution :
p - 7 < 3
Add 7 to each side.
So, the value of p is less than 10.
Problem 3 :
Solve for r :
2r ≤ 6
Solution :
2r ≤ 6
Divide each side by 2.
So, the value of r is less than or equal to 3.
Problem 4 :
Solve for m :
(1/4)m ≤ 3
Solution :
(1/4)m ≤ 3
Multiply each side by 4.
So, the value of m is less than or equal to 12.
Problem 5 :
Solve for p :
8 - p ≥ 12
Solution :
8 - p ≥ 12
In this problem, first we have to make p to be positive.
For that, we have to add p to each side.
When we do so, we will have (12 + p) on the right side of the inequality.
Then, subtract 12 from each side to solve for p.
or
p ≤ -4
So, the value of p is less than or equal to -4.
Problem 6 :
Solve for m :
m - 10 < -15
Solution :
m - 10 < -15
Add 10 to each side.
m < -5
So, the value of m is less than -5.
Problem 7 :
Solve for v :
v + 5/3 > -1/3
Solution :
v + 5/3 > -1/3
Subtract 5/3 from each side.
v > -2
So, the value of v is greater than -2.
Problem 8 :
Solve for m :
38 - m ≤ -44
Solution :
In this problem, first we have to make m to be positive.
For that, we have to add m to each side.
When we do so, we will have (-44 + m) on the right side of the inequality.
Then, add 44 to each side to solve for m.
82 ≤ m
m ≥ 82
So, the value of m is greater than 82.
Problem 9 :
Solve for m :
-11m > 22
Solution :
-11m > 22
Divide each side by -11.
m < -2
So, the value of m is less than -2.
Problem 10 :
Solve for v :
-25.7 - v < -40.3
Solution :
In this problem, first we have to make v to be positive.
For that, we have to add v to each side.
When we do so, we will have (-40.3 + v) on the right side of the inequality.
Then, add 40.3 to each side to solve for v.
14.6 < v
v > 14.6
So, the value of v is greater than 14.6.
Problem 11 :
When 7 is added to a number, we get the result greater than 25. Find the number.
Solution :
Let x be the required number.
Given : When 7 is added to the number, the result is greater than 25.
Then, we have
x + 7 > 25
Subtract 7 from each side.
x > 18
So, the required number is any number greater than 18.
Problem 12 :
When we multiply a number by 4, we get the result less than 124. Find the number.
Solution :
Let x be the required number.
Given : When the number is multiplied by 4, the result is less than 125.
Then, we have
4x < 124
Divide each side by 4.
x < 31
So, the required number is any number less than 31.
Problem 13 :
When we divide a number by 7, we get the result greater than 14. Find the number.
Solution :
Let m be the required number.
Given : When the number is divided by 7, the result is greater than 14.
m / 7 > 14
Multiply each side by 7.
m > 98
So, the required number is any number greater than 98.
Problem 14 :
John had some candies. He gave 5 candies to his friend and now he has more than 18 candies. How many candies did John initially have ?
Solution :
Let m be the no. of candies that John initially had.
Given : After giving 5 candies to friend, John has more than 18 candies.
Then, we have
m - 5 > 18
Add 5 to each side.
m > 23
So, John initially would have had more than 23 candies.
Problem 15 :
Alex borrowed some money from Jose. After 3 years, Alex returned more than 2 times of borrowed money to Jose. If the returned money is $226, how much money did Alex borrow from Jose ?
Solution :
Let x be the borrowed money.
Given : Alex returned more than 2 times of borrowed money to Jose. and the returned money is $226.
Then, we have
226 > 2x
Divide each side by 2.
113 > x
x < 113
So, the borrowed money is less than $113.
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