SOLVING QUADRATIC EQUATIONS WORKSHEET

Problem 1 :

Solve the quadratic equation by factoring :

x² – 5x – 24  =  0

Problem 2 :

Solve the quadratic equation by factoring :

3x² – 5x – 12  =  0

Problem 3 :

Solve the quadratic equation using quadratic formula :

15x² – 11x + 2  =  0

Problem 4 :

Solve the quadratic equation using quadratic formula :

(x + 3)² - 81  =  0

Problem 5 :

Solve the following quadratic equation by completing the square method.

x² - 6x - 16  =  0

Problem 6 :

Solve the following quadratic equation by completing the square method.

9x² - 12x + 4  =  0

Detailed Answer Key

Problem 1 :

Solve the quadratic equation by factoring :

x² – 5x – 24  =  0

Solution :

In the given quadratic equation, the coefficient of x² is 1.

Decompose the constant term -24 into two factors such that the product of the two factors is equal to -24 and the addition of two factors is equal to the coefficient of x, that is 5. 

Then, the two factors of -24 are 

+3 and -8

Factor the given quadratic equation using +3 and -8 and solve for x.

(x + 3)(x - 8)  =  0

x + 3  =  0  or  x - 8  =  0

x  =  -3  or  x  =  8

So, the solution is {-3, 8}. 

Problem 2 :

Solve the quadratic equation by factoring :

3x² – 5x – 12  =  0

Solution :

In the given quadratic equation, the coefficient of x² is not 1.

So, multiply the coefficient of x² and the constant term "-12". 

3 ⋅ (-12)  =  -36

Decompose -36 into two factors such that the product of two factors is equal to -36 and the addition of two factors is equal to the coefficient of x, that is -5.

Then, the two factors of -36 are 

+4 and -9

Now we have to divide the two factors 4 and -9 by the coefficient of x², that is 3.

Now, factor the given quadratic equation and solve for x as shown below. 

(3x + 4)(x - 3)  =  0

3x + 4  =  0  or  x - 3  =  0

x  =  -4/3  or  x  =  3

So, the solution is {-4/3, 3}. 

Problem 3 :

Solve the quadratic equation using quadratic formula :

15x² – 11x + 2  =  0

Solution : 

The given quadratic equation is in the form of 

ax² + bx + c  =  0

Comparing 

15x² – 11x + 2  =  0

and 

ax² + bx + c  =  0

we get 

a  =  15, b  =  -11 and c  =  2

Substitute the above values of a, b and c into the quadratic formula. 

Therefore, the solution is

{2/5, 1/3}

Problem 4 :

Solve the quadratic equation using quadratic formula :

(x + 3)² - 81  =  0 

Solution : 

Write the given quadratic equation in the form :

ax² + bx + c  =  0

Then, 

(x + 3)² - 81  =  0

(x + 3)(x + 3) - 81  =  0

x² + 3x + 3x + 9 - 81  =  0

x² + 6x - 72  =  0

Comparing 

x² + 6x - 72  =  0

and 

ax² + bx + c  =  0

we get 

a  =  1, b  =  6 and c  =  -72

Substitute the above values of a, b and c into the quadratic formula. 

Therefore, the solution is

{-12, 6}

Problem 5 :

Solve the following quadratic equation by completing the square method.

x² - 6x - 16  =  0

Solution :

Step 1 :

In the quadratic equation x² - 6x - 16 = 0, the coefficient of x² is 1. 

So, we have nothing to do in this step. 

Step 2 :

Add 16 to each side of the equation x² - 6x - 16  =  0.

x² - 6x  =  16

Step 3 :

In the result of step 2, write the "x" term as a multiple of 2. 

Then, 

x² - 6x  =  16

x² - 2(x)(3)  =  16

Step 4 :

Now add 3² to each side to complete the square on the left side of the equation.  

Then, 

x² - 2(x)(3) + 3²  =  16 + 3²

(x - 3)²  =  16 + 9

(x - 3)²  =  25

Take square root on both sides. 

√(x - 3)²  =  √25

x - 3  =  ±5

x - 3  =  -5  or  x - 3  =  5

x  =  -2  or  x  =  8

So, the solution is {-2, 8}. 

Problem 6 :

Solve the following quadratic equation by completing the square method.

9x² - 12x + 4  =  0

Solution :

Step 1 :

In the given quadratic equation 9x² - 12x + 4 = 0, divide the complete equation by 9 (coefficient of x²). 

  x² - (12/9)x + (4/9)  =  0

x² - (4/3)x + (4/9)  =  0

Step 2 :

Subtract 4/9 from each side. 

x² - (4/3)x  =  - 4/9

Step 3 :

In the result of step 2, write the "x" term as a multiple of 2. 

Then, 

x² - (4/3)x  =  - 4/9

x² - 2(x)(2/3)  =  - 4/9

Step 4 :

Now add (2/3)² to each side to complete the square on the left side of the equation.  

Then, 

x² - 2(x)(2/3) + (2/3)²  =  - 4/9 + (2/3)²

(x - 2/3)²  =  - 4/9 + 4/9

(x - 2/3)²  =  0

Take square root on both sides. 

√(x - 2/3)²  =  √0

x - 2/3  =  0

Add 2/3 to each side. 

x  =  2/3

So, the solution is 2/3. 

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