STEM AND LEAF PLOTS

A stem and leaf plot (often called as stem plot) is a way of writing down the data in groups is used for small data sets.

It shows actual data values and given visual comparison of frequencies.

For numbers with two digits, 

the first digit forms part of the stem and

the second digit forms part of the leaf.

For example, for the data value 17, 1 is recorded on the stem, and the 7 is a leaf value.

Make the stem and leaf plots for the given data :

Example 1 :

26, 37, 48, 33, 49, 26, 19, 26, 48

Solution :

Arrange the given data set in ascending order.

19, 26, 26, 26, 33, 37, 48, 48, 49

Example 2 :

67, 42, 58, 41, 54, 65, 65, 54, 69, 53

Solution :

Writing the given data values in ascending order, we get

41, 42, 53, 54, 54, 58, 65, 65, 67, 69

Example 3 :

For the ordered stem-and-leaf plot given, find:

(a)  the minimum value

(b)  the maximum value

Solution :

The first entry can be considered as minimum value

stem  =  0, leaf  =  1

Minimum value  =  1

The last entry can be considered as maximum value.

stem  =  4, leaf  =  3

Minimum value  =  43.

Example 4 :

A test score out of 60 marks is recorded for a group of 45 students :

34 37 44 51 53 39 33 58 40 42

43 43 47 37 35  41 43 48 50 55

44 44 52 54 59 39 31 29 44 57

45 34 29 27 18 49 41 42 37 42

43 43 45 34 51

a) Construct a stem-and-leaf plot for this data using 0, 1, 2, 3, 4, and 5 as the stems.

b) What advantage does a stem-and-leaf plot have over a frequency table?

c) What is the

i) highest     ii) lowest mark scored for the test?

d) If an ‘A’ is awarded to students who scored 50 or more for the test, what percentage of students scored an ‘A’?

e)  What percentage of students scored less than half marks for the test?

f)  Describe the distribution of the data.

Solution :

(a) 

(b)  The stem-and-leaf plot shows all the actual data values.

(c)  i)  Highest mark is 59

ii)  Lowest mark  =  18

(d) Total number of marks  =  45

Number of students who scores 50 or more than 50  =  10

Percentage  =  (10/45) x 100%

=  22.2 %

Percentage of students who scored more than 50 percentage of marks is 22.2%

(e)  Number of students who scored less than half mark

=  4

Percentage  =  (4/45) x 100%

=  8.88%

e) Negatively skewed with no outliers

Example 5 :

For the data set given, find:

a) the minimum value

b) the maximum value

c) the median

d)  the range

Solution :

(a)  The first entry is minimum value

stem  =  2, leaf  =  0

Minimum value  =  20

(b)  The last entry is maximum value

stem  =  5, leaf  =  8

Maximum value  =  58

c)  Total number of values  =  23

23 is odd, so median  =  (23+1)/2

=  24/2

Median  =  12th value

So, median is 40.

(d)  Range  =  maximum value - minimum value

=  58-20

=  38

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