1. The volume of the cube is 125 dm3. Find its side.
2. A container is in the shape of a cube of side 20 cm. How much sugar can it hold?
3. A cubical tank can hold 64,000 liters of water. Find the length of the side of the tank.
4. Three metallic cubes of side 3 cm, 4 cm and 5 cm respectively are melted and are recast into a single cube. Find the total surface area of the new cube.
5. Find the L.S.A, T.S.A and volume of a cube of side 5 cm.
6. Find the length of the side of a cube whose total surface area is 216 square cm.
7. A cube has a total surface area of 384 sq. cm. Find its volume.
8. If the lateral surface area of a cube is 900 cm2, find the length of its side.
1. Answer :
Volume of cube = 125 dm3
a3 = 125
a3 = 53
a = 5 dm
So, the side length of cube is 5 dm.
2. Answer :
In order to find the quantity of sugar that the container can hold, we have to find the volume of container.
Side length of cubical container = 20 cm
Volume of container = a3
= (20)3
= 8000 cm3
3. Answer :
Let a be the side of the cubical tank. Volume of the tank is 27,000 litres. So,
V = a3 = (27000/1000)
a3 = 27
a = ∛27
a = 3 m
4. Answer :
Side length of 1st cube = 3 cm
Side length of 2nd cube = 4 cm
Side length of 3rd cube = 5 cm
Volume of 1st, 2nd and 3rd cube = 33 + 43 + 53
= 27 + 64 + 125
= 216
a3 = 216
a3 = 63
a = 6 cm
Total surface area of new cube = 6a2
= 6(6)2
= 6(36)
= 216 cm2
So, total surface area of new cube 216 cm2
5. Answer :
Lateral surface area (L.S.A) = 4a2
= 4(52 ) = 100 sq. cm
Total surface area (T.S.A) = 6a2
= 6 (52 )
= 150 sq. cm
Volume of cube = a3
= 53
= 125 cm3
6. Answer :
Let a be the side of the cube.
Given that T.S.A = 216 sq. cm
6a2 = 216
a2 = 216/6
a2 = 36
a = √36
a = 6 cm
7. Answer :
Let a be the side of the cube. Given that T.S.A = 384 sq. cm
6a2 = 384
a2 = 384/6
a2 = 64
a = √64 = 8 cm
Hence, volume = a3 = 83 = 512 cm3
8. Answer :
Lateral surface area of cube = 4a2
4a2 = 900
a2 = 900/4
a2 = 225
a = √225
a = 15 cm
Hence the side of cube is 15 cm.
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