Question 1 :
From the top and foot of a 40 m high tower, the angles of elevation of the top of a lighthouse are found to be 30° and 60° respectively. Find the height of the lighthouse. Also find the distance of the top of the lighthouse from the foot of the tower.
Solution :
AB = x m and BD = 40 m
In triangle ABC :
∠ACB = 30°
tan θ = opposite side/Adjacent side
tan 30° = AB/BC
1/√3 = x/BC
BC = x√3 ----(1)
In triangle ADE :
∠AED = 60°
tan θ = opposite side/Adjacent side
tan 60° = AD/DE
√3 = (x + 40)/DE
DE = (x + 40)/√3 ---->(2)
(1) = (2)
x√3 = (x + 40)/√3
3 x = x + 40
3x - x = 40
2x = 40
x = 20
Height of the tower = 40 + 20 = 60 m
Question 2 :
The angle of elevation of a hovering helicopter as seen from a point 45 m above a lake is 30° and the angle of depression of its reflection in the lake, as seen from the same point and at the same time, is 60°. Find the distance of the helicopter from the surface of the lake.
Solution :
From the given information, we can draw a rough diagram
In a right triangle FAE :
tan θ = opposite side/Adjacent side
tan 30° = FE/AE
1/√3 = (h-45)/AE
AE = (h - 45) √3 ----(1)
In right triangle ACE :
tan θ = opposite side/Adjacent side
tan 60° = EC/AE
√3 = (ED+DC)/AE
√3 = (45+h)/AE
AE = (45 + h)/√3----(2)
(1) = (2) (BC = AD)
(h - 45) √3 = (45 + h)/√3
3(h - 45) = 45 + h
3h - 135 = 45 + h
2h = 45 + 135
2h = 180
h = 90
Hence the distance of the helicopter from the surface of the lake is 90 m.
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