Problem 1 :
Two dice are rolled once. Find the probability of getting an even number on the first die or a total of face sum 8.
Solution :
S = {(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6) (2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6) (3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6) (4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6) (5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6) (6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)}
Let "A" be the event of getting an even number on the first die
A = {(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6) (4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6) (6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)}
n(A) = 18
P(A) = n(A)/n(S)
P(A) = 18/36
Let "B" be the event of a total of face sum 8
B = {(2, 6) (3, 5) (4, 4) (5, 3) (6, 2)}
n(B) = 5
P(B) = n(B)/n(S)
P(B) = 5/36
A n B = {(2, 6) (4, 4) (6, 2)}
n(A n B) = 3
P(A n B) = n(AnB)/n(S)
P(A n B) = 3/36
P(A U B) = P(A) + P(B) - P(AnB)
P(A U B) = (18/36) + (5/36) - (3/36)
P(A U B) = (18 + 5 - 3)/36
P(A U B) = 20/36 = 5/9
Problem 2 :
From a well-shuffled pack of 52 cards, a card is drawn at random. Find the probability of it being either a red king or a black queen.
Solution :
Total number of cards n(S) = 52
Let "A" be the event of getting red king card.
n(A) = 2
P(A) = n(A) / n(S) = 2/52
Let "B" be the event of getting black queen card.
n(B) = 2
P(B) = n(B) / n(S) = 2/52
Since A and B are mutually exclusive events, A n B = 0
P(A U B) = P(A) + P(B) - P(A n B)
P(A U B) = (2/52) + (2/52) - 0
P(A U B) = 4/52
P(AUB) = 1/13
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