To find the area of the quadrilateral with the given four vertices, we may use the formula given below.
Question 1 :
Let P(11,7) , Q(13.5, 4) and R(9.5, 4) be the mid- points of the sides AB, BC and AC respectively of triangle ABC . Find the coordinates of the vertices A, B and C. Hence find the area of triangle ABC and compare this with area of triangle PQR
Solution :
To find the vertices of the triangle from the midpoint of the sides, please visit the page "https://www.onlinemath4all.com/how-to-find-the-vertices-of-a-triangle-if-the-midpoints-are-given.html"
Vertex A :
= (11 + 9.5 - 13.5, 7 + 4 - 4)
= A (7, 7)
Vertex B :
= (11 + 13.5 - 9.5, 7 + 4 - 4)
= B (15, 7)
Vertex C :
= (13.5 + 9.5 - 11, 4 + 4 - 7)
= C (12, 1)
Area of triangle ABC :
= (1/2)[(49 + 15 + 84) - (105 + 84 + 7)]
= (1/2)[148 - 196]
= 48/2
Area of triangle ABC = 24 square units
Area of triangle PQR :
P(11,7) , Q(13.5, 4) and R(9.5, 4)
= (1/2)[(44 + 54 + 66.5) - (94.5 + 38 + 44)]
= (1/2)[164.5 - 176.5]
= (1/2) (12)
Area of triangle PQR = 6
Area of triangle ABC = 4 (Area of triangle PQR)
Let us look into the next example on "Word Problems to Find Area of Quadrilaterals with Vertices".
Question 2 :
In the figure, the quadrilateral swimming pool shown is surrounded by concrete patio. Find the area of the patio.
Solution :
To find the area of patio, we have to subtract area of EFGH from area of ABCD.
Area of ABCD :
= (1/2)[(16 + 80 + 36 + 80) - (-64 - 24 - 100 - 24)]
= (1/2)[(212)-(-212)]
= (1/2)[212+212]
= 212 square units
Area of EFGH :
= (1/2)[(6 + 42 + 12 + 30) - (-30 - 6 - 42 - 12)]
= (1/2)[(90)-(-90)]
= (1/2)[90+90]
Area of EFGH = 90 square units
Area of patio = 212 - 90
= 122 square units.
Question 3 :
A triangular shaped glass with vertices at A(-5,-4) , B(1,6) and C(7,-4) has to be painted. If one bucket of paint covers 6 square feets, how many buckets of paint will be required to paint the whole glass, if only one coat of paint is applied.
Solution :
Area of triangle ABC =
= (1/2)[(-30 - 4 - 28) - (-4 + 42 + 20)]
= (1/2)[-62 - (58)]
= (1/2)[-62 - 58]
= (1/2)(120)
= 60 square feet
Area covered by one bucket of paint = 6 square feets
Required number of bucket = 60 / 6
= 10 buckets
Question 4 :
In the figure, find the area of (i) triangle AGF (ii) triangle FED (iii) quadrilateral BCEG
Solution :
(i) triangle AGF
= (1/2) [(-2.5 - 13.5 - 6) - (-13.5 - 1 - 15)]
= (1/2) [(-22) - (-29.5)]
= (1/2) (-22+29.5)
= (1/2)[7.5]
= 3.75 square units.
(ii) triangle FED
F (-2, 3) E (1.5, 1) and D (1, 3)
= (1/2)[(-2 + 4.5 + 3) - (4.5 + 1 - 6)]
= (1/2)[(5.5) - (-0.5)]
= (1/2)6
Area of triangle FED = 3 square units.
(iii) B (-4, -2) C (2, -1) E (1.5, 1) G (-4.5, 0.5)
= (1/2)[(4 + 2 + 0.75 + 9) - (-4 - 1.5 - 4.5 - 2)]
= (1/2)[(15.75) - (-12)]
= (1/2)(15.75 + 12)
= (1/2)(27.75)
= 13.875 square units.
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