Problem 1 :
If a vector and b vector represent a side and a diagonal of a parallelogram, find the other sides and the other diagonal.
Solution :
AB vector = a vector, AC vector = b vector
AB vector + BC vector = AC vector
BC vector = AC vector - AB vector
BC vector = b vector - a vector
The sides AB and CD are in opposite direction.
CD vector = -AB vector = -a vector
CD vector = - a vector
AD vector = b vector - a vector
To find the length of DA, we have to multiply AD vector by negative.
- AD vector = -(b vector - a vector)
DA vector = a vector - b vector
Now let us find the length of other diagonal BD.
AB vector + BD vector = AD vector
BD vector = AD vector - AB vector
= b vector - a vector - a vector
BD vector = b vector - 2a vector
Problem 2 :
If PO vector + OQ vector = QO vector +OR vector, prove that the points P, Q, R are collinear.
Solution :
PO vector + OQ vector = QO vector +OR vector
-OP vector + OQ vector = -OQ vector + OR vector
OQ vector - OP vector = OR vector - OQ vector
PQ vector = QR vector
Because they are equal, they are parallel and they have a common point Q.
So, the points P, Q and R are collinear.
Problem 3 :
If D is the midpoint of the side BC of a triangle ABC, prove that AB vector + AC vector = 2AD vector.
Solution :
From the given information, let us draw a rough diagram.
In triangle ABD,
AB vector + BD vector = AD vector
AB vector = AD vector - BD vector ---(1)
In triangle ADC,
AD vector + DC vector = AC vector
AC vector = AD vector + DC vector ----(2)
(1) + (2)
AB vector + AC vector = AD vector - BD vector + AD vector + DC vector
AB vector + AC vector = 2AD vector - BD vector + DC vector. Since BD and DC are in same magnitude, they will get canceled.
AB vector + AC vector = 2AD vector
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