Problem 1-4 : Solve the quadratic equation using the quadratic formula.
Problem 1 :
x2 + 8x + 5 = 0
Problem 2 :
2x2 + 6x + 1 = 0
Problem 3 :
x2 + 2x = 2
Problem 4 :
x2 + 2 = 6x
Problem 5 :
3x2 + 2x – 2 = 0
Problem 6 :
x + ¹⁄ₓ = 3
Problem 7 :
(x + 2)(x – 1) = 5
Problem 8 :
x + ¹⁄₍ₓ ₊ ₂₎ = 4
Problem 9 :
(x + 1)2 = 3 – x2
Problem 10 :
1. Answer :
Comparing ax2 + bx + c = 0 and x2 + 8x + 5 = 0 = 0, we get
a = 1, b = 8, c = 5
Quadratic Formula :
Substitute a = 1, b = 8 and c = 5.
x = -4 ± √11
x = -4 + √11 or -4 - √11
2. Answer :
2x2 + 6x + 1 = 0
From the above quadratic equation, we have
a = 2, b = 6, c = 1
Substitute the above values into the quadratic formula.
3. Answer :
x2 + 2x = 2
Subtract 2 from both sides.
x2 + 2x - 2 = 0
From the above quadratic equation, we have
a = 1, b = 2, c = -2
Substitute the above values into the quadratic formula.
x = -1 ± √3
x = -1 + √3 or -1 - √3
4. Answer :
x2 + 2 = 6x
Subtract 6x from both sides.
x2 - 6x + 2 = 0
From the above quadratic equation, we have
a = 1, b = -6, c = 2
Substitute the above values into the quadratic formula.
x = 3 ± √7
x = 3 + √7 or 3 - √7
5. Answer :
3x2 + 2x – 2 = 0
From the above quadratic equation, we have
a = 3, b = 2, c = -2
Substitute the above values into the quadratic formula.
6. Answer :
x + ¹⁄ₓ = 3
Multiply both sides by x.
x(x + ¹⁄ₓ) = x(3)
x2 + 1 = 3x
Subtract 3x from both sides.
x2 - 3x + 1 = 0
From the above quadratic equation, we have
a = 1, b = -3, c = 1
Substitute the above values into the quadratic formula.
7. Answer :
(x + 2)(x – 1) = 5
x2 - x + 2x - 2 = 5
x2 + x - 2 = 5
Subtract 5 from both sides.
x2 + x - 7 = 0
From the above quadratic equation, we have
a = 1, b = 1, c = -7
Substitute the above values into the quadratic formula.
8. Answer :
x + ¹⁄₍ₓ ₊ ₂₎ = 4
Multiply both sides by (x + 2).
(x + 2)[x + ¹⁄₍ₓ ₊ ₂₎] = 4(x + 2)
x(x + 2) + (x + 2)[¹⁄₍ₓ ₊ ₂₎] = 4x + 8
x2 + 2x + 1 = 4x + 8
Subtract 4x and 8 from both sides.
x2 - 2x - 7 = 0
From the above quadratic equation, we have
a = 1, b = -2, c = -7
Substitute the above values into the quadratic formula.
x = 1 ± 2√2
x = 1 + 2√2 or 1 - 2√2
9. Answer :
(x + 1)2 = 3 – x2
x2 + 2x + 1 = 3 – x2
Add x2 to both sides.
2x2 + 2x + 1 = 3
Subtract 3 from both sides.
2x2 + 2x - 2 = 0
Divide both sides by 2.
x2 + x - 1 = 0
From the above quadratic equation, we have
a = 1, b = 1, c = -1
Substitute the above values into the quadratic formula.
10. Answer :
(x + 2)(x + 1) = 3x(x - 1)
x2 + x + 2x + 2 = 3x2 - 3x
x2 + 3x + 2 = 3x2 - 3x
2x2 - 6x - 2 = 0
Divide both sides by 2.
x2 - 3x - 1 = 0
From the above quadratic equation, we have
a = 1, b = -3, c = -1
Substitute the above values into the quadratic formula.
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