Exponents are used to avoid the repetition of writing the same numerical values many times.
Write each number in exponent form :
Example 1 :
2 × 2 × 3 × 3 × 3
Solution :
2 × 2 × 3 × 3 × 3
2 is repeated 2 times and 3 is repeated 3 times.
= 22 × 33
Example 2 :
2 × 5 × 5
Solution :
2 × 5 × 5
2 is repeated once and 5 is repeated 2 times.
= 2 × 52
Example 3 :
2 × 3 × 3 × 3 × 5
Solution :
2 × 3 × 3 × 3 × 5
2 and 5 are repeated once and 3 is repeated 3 times.
= 2 × 33 × 5
Example 4 :
5 × 5 × 7 × 7
Solution :
5 × 5 × 7 × 7
5 is repeated twice and 7 is repeated twice.
= 52 × 72
Example 5 :
2 × 2 × 5 × 5 × 5 × 7
Solution :
2 × 2 × 5 × 5 × 5 × 7
2 is repeated twice, 5 is repeated 3 times and 7 is repeated once.
= 22 × 53 × 7
Example 6 :
3 × 3 × 7 × 7 × 11 × 11
Solution :
3 × 3 × 7 × 7 × 11 × 11
3, 7 and 11 are repeated twice.
= 32 × 72 × 112
Example 7 :
56
Solution :
Since 56 is a composite number, we can decompose it into prime factors.
Prime factorization of 56 :
56 = 2 x 2 x 2 x 7
2 is repeated 3 times and 7 is repeated once.
= 23 x 7
Example 8 :
24
Solution :
By decomposing 24 as prime factors, we get
Prime factorization of 24 :
24 = 2 x 2 x 2 x 3
2 is repeated 3 times and 3 is repeated once.
= 23 x 3
Example 9 :
108
Solution :
By decomposing 108 as prime factors, we get
Prime factorization of 108 :
108 = 2 x 2 x 3 x 3 x 3
2 is repeated 2 times and 3 is repeated 3 times.
= 22 x 33
Example 10 :
80
Solution :
By decomposing 80 as prime factors, we get
Prime factorization of 80 :
80 = 2 x 2 x 2 x 2 x 5
2 is repeated 4 times and 5 is repeated once.
= 24 x 5
Example 11 :
83 x 84 is equal to
a) 812 b) 647 c) 221 d) None of these
Solution :
= 83 x 84
When we have two which are multiplied, we get
= 83+4
= 87
Example 12 :
Which of the following is equal to
3 x 3 x 3 x 3 x 3 x 3
a) 36 b) 18 c) 93 d) 729
Solution :
= 3 x 3 x 3 x 3 x 3 x 3
Here 3 is multiplied six times, to convert into exponential form, we get
= 86
Example 13 :
(42)3
a) 48 b) 46 c) 45 d) 423
Solution :
(42)3
When we have power raised by another power, we have to multiply the powers.
= 4(2x3)
= 46
Example 14 :
2.7 x 10-3 is equal to
a) 0.000027 b) 0.00027 c) 0.0027 d) 2.007
Solution :
2.7 x 10-3
Converting the negative exponent to positive exponent, we get
= 2.7 x (1/103)
= 2.7/103
= 2.7/1000
Moving the decimal 3 digits to the left. We get
= 0.0027
So, option c is correct.
Example 15 :
(-1)1001 is equal to
a) 1 b) -1 c) 1001 d) 0
Solution :
(-1)1001
1001 is odd number, multiplying -1 odd number of times. We get -1 as result. So, option b is correct.
Example 16 :
The value of (-2)5 is equal to
a) -32 b) 10 c) 1/32 d) -1/32
Solution :
(-2)5
Since we have negative base and multiplying this odd number of times, we get the answer with negative sign.
= -32
So, option a is correct.
Example 17 :
Express 2 x 3 x 2 x 3 x 2 x 3 x 2 x 3 in exponential form.
Solution :
= 2 x 3 x 2 x 3 x 2 x 3 x 2 x 3
Here 2 is multiplied four times and 3 is multiplied four time. Writing it in exponential form, we get
= 24 x 34
= (2 x 3)4
= 64
Example 18 :
Express 79 in the product form.
Solution :
= 79
Since we have 9 at the power, we have to repeat the base nine times.
= 7 x 7 x 7 x 7 x 7 x 7 x 7 x 7 x 7
Example 18 :
Express (3/4)3 in the form of p/q.
Solution :
= (3/4)3
= (3 x 3 x 3)/(4 x 4 x 4)
= 27/64
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