Problem 1 :
There are 2 red jacks in a standard deck of 52 cards. What is the probability of not getting a red jack if you select one card at random ?
Problem 2 :
A jar contains 8 marbles marked with the numbers 1 through 8. If you pick a marble at random, what is the probability of not picking the marble marked with the number 5 ?
Problem 1 :
There are 2 red jacks in a standard deck of 52 cards. What is the probability of not getting a red jack if you select one card at random ?
Solution :
Step 1 :
P(event) + P(complement) = 1
P(red jack) + P(not a red jack) = 1
Step 2 :
The probability of getting a red jack is 2/52.
Substitute 2/52 for P(red jack).
2/52 + P(not a red jack) = 1
Step 3 :
Subtract 2/52 from both sides.
[2/52 + P(not a red jack)] - 2/52 = 1 - 2/52
P(not a red jack) = 52/52 - 2/52
P(not a red jack) = (52 - 2)/52
P(not a red jack) = 50/52
Simplify.
P(not a red jack) = 25/26
The probability that you will not draw a red jack is 25/26. It is likely that you will not select a red jack.
Problem 2 :
A jar contains 8 marbles marked with the numbers 1 through 8. If you pick a marble at random, what is the probability of not picking the marble marked with the number 5 ?
Solution :
Step 1 :
P(event) + P(complement) = 1
P(marble numbered 5) + P(not the marble numbered 5 ) = 1
Step 2 :
The probability of getting a marble numbered 5 is 1/8.
Substitute 1/8 for P(marble numbered 5).
1/8 + P(not the marble numbered 5) = 1
Step 3 :
Subtract 1/8 from both sides.
[1/8 + P(not the marble numbered 5)] - 1/8 = 1 - 1/8
P(not the marble numbered 5) = 8/8 - 1/8
P(not the marble numbered 5) = (8 - 1)/8
P(not the marble numbered 5) = 7/8
The probability that you will not pick a marble numbered with 5 is 7/8 . It is likely that you will not pick a marble numbered with 5.
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