Question 1 :
If the sides of a cubic box are increased by 1, 2, 3 units respectively to form a cuboid, then the volume is increased by 52 cubic units. Find the volume of the cuboid.
Solution :
Let x be the side length of the cube
Volume of cube is
= x3
Length of cuboid = (x + 1)
Breadth of cuboid = (x + 2)
Height of cuboid = (x + 3)
Volume of cuboid = (x + 1) (x + 2) (x + 3)
(x + 1) (x + 2) (x + 3) = 52
(x2 + 3x + 2) (x + 3) = 52
x3 + 3x2 + 3x2 + 9x + 2x + 6 = x3 + 52
x3 - x3 + 6x2 + 11x + 6 - 52 = 0
6x2 + 11x - 46 = 0
6x2 - 12x + 23x - 46 = 0
6x (x - 2) + 23(x - 2) = 0
6x + 23 = 0, x - 2 = 0
x = 2
Volume of cube is
= x3
= 23
= 8 cubic units.
Question 2 :
Construct a cubic equation with roots.
(i) 1, 2 and 3 (ii) 1,1, and −2 (iii) 2, 1/2 and 1.
Solution :
(i) 1, 2 and 3
x = 1, x = 2 and x = 3
(x - 1) (x - 2) (x - 3) = 0
(x2 - 2x - x + 2)(x - 3) = 0
(x2 - 3x + 2)(x - 3) = 0
x3 - 3x2 - 3x2 + 9x + 2x - 6 = 0
x3 - 6x2 + 11x - 6 = 0
(ii) 1, 1 and −2
x = 1, x = 1 and x = -2
(x - 1) (x - 1) (x + 2) = 0
(x2 - x - x + 1)(x + 2) = 0
(x2 - 2x + 1)(x + 2) = 0
x3 + 2x2 - 2x2 - 4x + 1x + 2 = 0
x3 - 3x + 2 = 0
(iii) 1, 1/2 and 1
x = 1, x = 1/2 and x = 1
(x - 1) (x - 1/2) (x - 1) = 0
(x - 1)2(x - 1/2) = 0
(x2 - 2x + 1) (2x - 1)/2) = 0
2x3 - x2 - 4x2 + 2x + 2x - 1 = 0
2x3 - 5x2 + 4x - 1 = 0
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