Question 1 :
Find the derivative of ex with respect to x.
or
Given y = ex, find dy/dx.
(x and y are variables and e is a constant)
Question 2 :
Find the derivative emx with respect to x, where m is a constant.
Question 3 :
Find the derivative e-x with respect to x.
Question 4 :
Find dy/dx :
Question 5 :
Find dy/dx :
Question 6 :
Find the derivative e2 with respect to x.
Question 7 :
Find the derivative of ax with respect to x.
or
Given y = ax, find dy/dx.
(x and y are variables and a is a constant)
Question 8 :
If y = 5x, find dy/dx.
Question 9 :
Find the derivative of xx with respect to x.
or
Find dy/dx, if y = xx.
Question 10 :
Find the derivative of aa with respect to x.
or
Given y = aa, find dy/dx.
(a is a constant)
1. Answer :
In y = ex, we have constant e in base and variable x in exponent.
y = ex
Take logarithm on both sides.
lny = lnex
Apply the power rule of logarithm on the right side.
lny = xlne
(The base of a natural logarithm is e, lne is a natural logarithm and its base is e)
lny = xlnee
In a logarithm, if the base and argument are same, its value is 1. In lnee, the base and argument are same, so its value is 1.
lny = x(1)
lny = x
Find the derivative with respect to x.
(1/y)(dy/dx) = 1
Multiply both sides by y.
dy/dx = y
Substitute y = ex.
dy/dx = ex
Therefore, the derivative ex is ex.
Note :
In general, the derivative of ex is ex. That is, the derivative of evariable is the same evariable.
Using chain rule, we can explain the derivative of ex.
That is, the derivative of ex is ex. So, far we have completed the derivative only for ex, further, we have to find the derivative of the exponent x with respect to x, by chain rule.
y = ex
dy/dx = ex(1)
dy/dx = ex
2. Answer :
The derivative of emx is emx, further, find the derivative of the exponent mx with respect to x. By chain rule. derivative of mx with respect to x is m(1) = m.
y = emx
dy/dx = ex⋅ m(1)
dy/dx = mex
So, the derivative emx with respect to x is mex.
3. Answer :
The derivative of e-x is e-x, further, find the derivative of the exponent -x with respect to x. By chain rule. derivative of -x with respect to x is -1.
y = e-x
dy/dx = e-x⋅ (-1)
dy/dx = -e-x
So, the derivative e-x with respect to x is e-x.
4. Answer :
5. Answer :
6. Answer :
The derivative of e2 is e2, further, find the derivative of the exponent 2 with respect to x. By chain rule. derivative of 2 with respect to x is 0.
y = e2
dy/dx = e2⋅ (0)
dy/dx = 0
So, the derivative e2 with respect to x is zero.
Note :
We know that e is a mathematical constant and number 2 is a constant. So, e2 is a constant. Since the derivative of a constant is zero, the derivative e2 is zero.
Derivative of e to the power of any constant is zero.
7. Answer :
In y = ax, we have constant a in base and variable x in exponent.
y = ax
Take logarithm on both sides.
lny = lnax
Apply the power rule of logarithm on the right side.
lny = xlna
Find the derivative with respect to x.
(1/y)(dy/dx) = (1)lna
(since, a is a constant, lna is also a constant. When we find derivative xlna, we keep the the constant lna as it is and find the derivative of x with respect to x, that is 1)
Multiply both sides by y.
dy/dx = ylna
Substitute y = ax.
dy/dx = axlna
Therefore, the derivative ax is axlna.
8. Answer :
y = 5x
dy/dx = 5xln5
9. Answer :
In y = xx, we have variable x in exponent.
y = xx
Take logarithm on both sides.
lny = lnxx
Apply the power rule of logarithm on the right side.
lny = xlnx
Find the derivative with respect to x.
(1/y)(dy/dx) = x(1/x) + lnx(1)
(to find the derivative of xlnx, product rule is used)
(1/y)(dy/dx) = 1 + lnx
Multiply both sides by y.
dy/dx = y(1 + lnx)
Substitute y = xx.
dy/dx = xx(1 + lnx)
Therefore, the derivative xx is xx(1 + lnx).
10. Answer :
In y = aa, In both exponent and base, we have the constant a.
Since a is a constant, aa is also a constant.
y = aa
dy/dx = 0
Since the derivative of a constant is zero, the derivative of aa is zero.
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