Problems 1-12 : Write each quadratic trinomial in factored form (as the product of two binomials).
Problem 1 :
x2 + 14x + 48
Problem 2 :
y2 + 10y + 16
Problem 3 :
m2 + 14m + 40
Problem 4 :
k2 + 9k + 18
Problem 5 :
n2 - 8n + 7
Problem 6 :
a2 - 9a + 14
Problem 7 :
c2 - 8c + 15
Problem 8 :
x2 - 16m + 63
Problem 9 :
y2 - 4y - 60
Problem 10 :
k2 + k - 6
Problem 11 :
p2 - 2p - 15
Problem 12 :
r2 + r - 20
Problems 13-18 : Factor each completely. (Remember to pull out the greatest common factor first.)
Problem 13 :
3x2 + 21x + 30
Problem 14 :
2y2 + 14y + 24
Problem 15 :
2m2 - 16m + 30
Problem 16 :
3k2 - 9k + 6
Problem 17 :
3n2 - 3n - 36
Problem 18 :
2a2 + 2a - 12
1. Answer :
= x2 + 14x + 48
= x2 + 8x + 6x + 48
= x(x + 8) + 6(x + 8)
= (x + 8)(x + 6)
2. Answer :
= y2 + 10y + 16
= y2 + 8y + 2y + 16
= y(y + 8) + 2(y + 8)
= (y + 8)(y + 2)
3. Answer :
= m2 + 14m + 40
= m2 + 10m + 4m + 40
= m(m + 10) + 4(m + 10)
= (m + 10)(m + 4)
4. Answer :
= k2 + 9k + 18
= k2 + 6k + 3k + 18
= k(k + 6) + 3(k + 6)
= (k + 6)(k + 3)
5. Answer :
= n2 - 8n + 7
= n2 - 7n - 1n + 7
= n(n - 7) - 1(n - 7)
= (n - 7)(n - 1)
6. Answer :
= a2 - 9a + 14
= a2 - 7a - 2a + 14
= a(a - 7) - 2(a - 7)
= (a - 7)(a - 2)
7. Answer :
= c2 - 8c + 15
= c2 - 5c - 3c + 15
= c(c - 5) - 3(c - 5)
= (c - 5)(c - 3)
8. Answer :
= m2 - 16m + 63
= m2 - 9m - 7m + 63
= m(m - 9) - 7(m - 9)
= (m - 9)(m - 7)
9. Answer :
= y2 - 4y - 60
= y2 - 10y + 6y - 60
= y(y - 10) + 6(y - 10)
= (y - 10)(y + 6)
10. Answer :
= k2 + k - 6
= k2 + 3k - 2k - 6
= k(k + 3) - 2(k + 3)
= (k + 3)(k - 2)
11. Answer :
= p2 - 2p - 15
= p2 - 5p + 3p - 15
= p(p - 5) + 3(p - 5)
= (p - 5)(p + 3)
12. Answer :
= r2 + r - 20
= r2 + 5r - 4r - 20
= r(r + 5) - 4(r + 5)
= (r + 5)(r - 4)
13. Answer :
= 3x2 + 21x + 30
= 3(x2 + 7x + 10)
= 3(x2 + 5x + 2x + 10)
= 3[x(x + 5) + 2(x + 5)]
= 3(x + 5)(x + 2)
14. Answer :
= 2y2 + 14y + 24
= 2(y2 + 7y + 12)
= 2(y2 + 4y + 3y + 12)
= 2[y(y + 4) + 3(y + 4)]
= 2(y + 4)(y + 3)
15. Answer :
= 2m2 - 16m + 30
= 2(m2 - 8m + 15)
= 2(m2 - 5m - 3m + 15)
= 2[m(m - 5) - 3(m - 5)]
= 2(m - 5)(m - 3)
16. Answer :
= 3k2 - 9k + 6
= 3(k2 - 3k + 2)
= 3(k2 - 2k - 1k + 2)
= 3[k(k - 2) - 1(k - 2)]
= 3(k - 2)(k - 1)
17. Answer :
= 3n2 - 3n - 36
= 3(n2 - n - 12)
= 3(n2 - 4n + 3n - 12)
= 3[n(n - 4) + 3(n - 4)]
= 3(n - 4)(n + 3)
18. Answer :
= 2a2 + 2a - 12
= 2(a2 + a - 6)
= 2(a2 + 3a - 2a - 6)
= 2[a(a + 3) - 2(a + 3)]
= 2(a + 3)(a - 2)
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