Symmetric about x - axis and y - axis :
Right V (0, 0) F (a, 0) |
Left V (0, 0) F (-a, 0) |
Up V (0, 0) F (0, a) |
Down V (0, 0) F (0, -a) |
Equation of latus rectum
x = a |
x = -a |
y = a |
y = -a |
Equation of directrix :
x = -a |
x = a |
y = -a |
y = a |
Symmetric about x - axis and y - axis :
Right V (h, k) F (h + a, k) |
Left V (h, k) F (h-a, k) |
Up V (h, k) F (h, k + a) |
Down V (h, k) F (h, k-a) |
Equation of latus rectum :
x = h + a |
x = h - a |
y = k + a |
y = k - a |
Equation of directrix :
x = h-a |
x = h + a |
y = k - a |
y = k + a |
Question :
Find the vertex, focus, equation of directrix and length of the latus rectum of the following:
(i) y2 = 16x
Solution :
From the given information, we come to know that the given parabola is symmetric about x-axis and open right ward.
4a = 16
a = 4
Vertex : V (0, 0)
Focus : F (a, 0) ==> F(4, 0)
Equation of latus rectum : x = a ==> x = 4
Equation of directrix : x = -a ==> x = -4
Length of latus rectum = 4a = 4(4) = 16
Let us look into the next problems on "Find Vertex Focus Directrix and Latus Rectum of Parabola"
(ii) x2 = 24y
Solution :
From the given information, we come to know that the given parabola is symmetric about y-axis and open upward.
4a = 24
a = 6
Vertex : V (0, 0)
Focus : F (0, a) ==> F(0, 6)
Equation of latus rectum : y = a ==> y = 6
Equation of directrix : y = -a ==> y = -6
Length of latus rectum = 4a = 4(6) = 24
(iii) y2 = −8x
Solution :
From the given information, we know that the given parabola is symmetric about x-axis and left upward.
4a = 8
a = 2
Vertex : V (0, 0)
Focus : F (-a, 0) ==> F(-2, 0)
Equation of latus rectum : x = -a ==> x = -2
Equation of directrix : x = a ==> x = 2
Length of latus rectum = 4a = 4(2) = 8
(iv) x2 - 2x + 8y + 17 = 0
Solution :
x2 - 2x + 8y + 17 = 0
x2 - 2 ⋅ x ⋅ 1 + 12 - 12 + 8y + 17 = 0
(x - 1)2 - 1 + 8y + 17 = 0
(x - 1)2 = -8y - 16
(x - 1)2 = -8(y + 2)
The parabola is symmetric about y-axis and open downward.
4a = 8
a = 2
Vertex : V(h, k) ==> (1, -2)
Focus : F (h, k - a) ==> F (1, -4)
Equation of directrix : y = k + a ==> y = -2 + 2 = 0
Length of latus rectum = 4a = 4(2) = 8
(v) y2 - 4y - 8x + 12 = 0
Solution :
y2 - 4y - 8x + 12 = 0
y2 - 2 ⋅ y ⋅2 + 22 - 22 - 8x + 12 = 0
(y - 2)2 - 4 = 8x - 12
(y - 2)2 = 8x - 8
(y - 2)2 = 8(x - 1)
The parabola is symmetric about x-axis and open rightward.
4a = 8
a = 2
Vertex : V(h, k) ==> (1, 2)
Focus : F (h+a, k) ==> F (3, 2)
Equation of directrix : x = h - a ==> x = -1
Length of latus rectum = 4a = 4(2) = 8
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