Let A be a square matrix of order n. If there exists a square matrix B of order n such that
AB = BA = In
then the matrix B is called an inverse of A.
Note :
Let A be square matrix of order n. Then, A−1 exists if and only if A is non-singular.
Example 1 :
Find the inverse (if it exists) of the following:
Since |A| = 2 ≠ 0, it is non singular matrix. A-1 exists.
Example 2 :
Solution :
In order to find inverse of a matrix, first we have to find |A|.
|A| = 5(25 - 1) - 1(5 - 1) + 1(1 - 5)
= 5(24 ) - 1(4) + 1(-4)
= 120 - 4 - 4
= 112
Since |A| = 112 ≠ 0, it is non singular matrix. A-1 exists.
Example 3 :
Solution :
In order to find inverse of a matrix, first we have to find |A|.
|A| = 2(8 - 7) - 3(6 - 3) + 1(21 - 12)
= 2(1) - 3(3) + 1(9)
= 2 - 9 + 9
= 2
Since |A| = 2 ≠ 0, it is non singular matrix. A-1 exists.
Example 4 :
Solution :
Let A = F(α)
A-1 = (1/|A|) adj A
|A| = cos α [cos α - 0] - 0[0 - 0] + sin α[0 + sin α]
= cos2α + sin2α
|A| = 1
Hence proved.
Example 5 :
Solution :
= A2 - 3A - 7I2
Finding the value of A2 :
Finding the value of 3A :
Finding the value of 7I2 :
A2 - 3A - 7I2
Hence proved.
Apart from the stuff given in this section, if you need any other stuff in math, please use our google custom search here.
Kindly mail your feedback to v4formath@gmail.com
We always appreciate your feedback.
©All rights reserved. onlinemath4all.com
Nov 15, 24 07:14 PM
Nov 15, 24 07:12 PM
Nov 15, 24 01:21 AM