FINDING MEAN FOR GROUPED DATA EXAMPLES

Question 1 :

If the mean of the following data is 20.2, then find the value of p

x

10

15

20

25

30

f

6

8

p

10

6

---

30 + p

fx

60

120

20p

250

180

-------

610 + 20p

Mean  =  (610 + 20p)/(30 + p)

Mean  =  20.2

(610 + 20p)/(30+p)  =  20.2

610 + 20p  =  20.2(30+p)

610 + 20 p = 606 + 20.2p

20.2p-20p  =  610 - 606

0.2p  =  4

p  =  4/0.2

p  =  20

Question 2 :

In the class, weight of students is measured for the class records. Calculate mean weight of the class students using Direct method.

Solution :

Weight

15-25

25-35

35-45

45-55

55-65

65-75

Mid value(x)

20

30

40

50

60

70

f

4

11

19

14

0

2

fx

80

330

760

700

0

140

-----

2010

Mean  =  2010 / 6

  =  335

Question 3 :

Calculate the mean of the following distribution using Assumed Mean Method:

Solution :

A = 25

Weight

0-10

10-20

20-30

30-40

40-50

Mid value(x)

5

15

25

35

45

f

5

7

15

28

8

--

63

d = x - 25

-20

-10

0

10

20

fd

-100

-70

0

280

160

-------

270

Mean  =  A +  fd/ f

=  25 + (270/63)

=  25 + 4.28

Mean  =  29.28

Question 4 :

Find the Arithmetic Mean of the following data using Step Deviation Method:

Solution :

Weight

14.5-19.5

19.5-24.5

24.5-29.5

29.5-34.5

34.5-39.5

39.5-44.5

x

17

22

27

32

37

42

f

4

20

38

24

10

9

--

105

d=(x-32)/5

-15 => -3

-10 => -2

-5 => -1

0 => 0

5 => 1

10 => 2

fd

-12

-40

-38

0

10

18

-------

-62

Mean  =  A + ( fd/f) x c

=  32 + (-62/105) x 5

=  32 - 0.59 (5)

=  32 - 2.95

Mean  =  29.05

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