Question :
Determine the exact values of sin θ, cos θ and tan θ if the terminal arm of an angle in standard position passes through the given point.
a) P (-5, 12)
Solution :
Horizontal distance = 5, vertical distance = 12
Length of hypotenuse side = √122 + 52
= √(144 + 25)
= √169
= 13
Since the terminal arm lies in second quadrant, we have to use positive sign for sin and cosec.
sin θ = 12/13, cos θ = -5/13 and tan θ = -12/5
(b) P(5, -3)
Solution :
Horizontal distance = 5, vertical distance = 3
Length of hypotenuse side = √52 + 32
= √(25 + 9)
= √34
Since the terminal arm lies in fourth quadrant, we have to use positive sign for cos and sec.
sin θ = -5/√34, cos θ = 3/√34 tan θ = -5/3
(c) P(6, 3)
Solution :
Horizontal distance = 6, vertical distance = 3
Length of hypotenuse side = √62 + 32
= √(36 + 9)
= √45 = 3√5
Since the terminal arm lies in first quadrant, we have to use positive sign for all trigonometric ratios.
sin θ = 3/3√5 = 1/√5
cos θ = 6/3√5 = 2/√5
tan θ = 1/2
d) P(-24, -10)
Solution :
Horizontal distance = 24, vertical distance = 10
Length of hypotenuse side = √242 + 102
= √(576 + 100)
= √676 = 26
Since the terminal arm lies in third quadrant, we have to use positive sign for tan and cot only.
sin θ = -10/26 = -5/13
cos θ = -24/26 = -12/13
tan θ = 5/12
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