To multiply two matrices, the number of columns in the first matrix must be equal to the number of rows in the second matrix.
Consider the multiplications of 3×3 and 3×2 matrices.
(Order of left hand matrix) x (order of right hand matrix) -> (order of product matrix).
(3 × 3 ) x (3 × 2 ) -> (3 × 2 )
The product AB can be found if the number of columns of matrix A is equal to the number of rows of matrix B. If the order of matrix A is m x n and B is n x p then the order of AB is m x p .
Question 1 :
Find the order of the product matrix AB if
Solution :
(i) Order of A is 3 x 3, order of B is 3 x 3.
The order of the matrix AB is 3 x 3.
(ii) Order of A is 4 x 3, order of B is 3 x 2.
The order of the matrix AB is 4 x 2.
(iii) Order of A is 4 x 2, order of B is 2 x 2.
The order of the matrix AB is 4 x 2.
(iv) Order of A is 4 x 5, order of B is 5 x 1.
The order of the matrix AB is 4 x 1.
(v) Order of A is 1 x 1, order of B is 1 x 3.
The order of the matrix AB is 1 x 3.
Question 2 :
If A is of order p x q and B is of order q x r what is the order of AB and BA?
Solution :
(p x q) (q x r) = p x r
The order of matrix AB is p x r.
(q x r) (p x q) = p x r
The product of matrices B and A is not possible.
Hence it is not defined.
Question 3 :
A has ‘a’ rows and ‘a + 3 ’ columns. B has ‘b’ rows and ‘17–b’ columns, and if both products AB and BA exist, find a, b?
Solution :
Number of rows of A = a
Number of columns of A = a + 3
Number of rows of B = b
Number of columns of A = 17 - b
Since the product of matrices A and B is possible,
[a x (a + 3)] [b x (17 - b)]
a + 3 = b
a - b = -3 -----(1)
Since the product of matrices B and A is possible,
[b x (17 - b)] [a x (a + 3)]
17 - b = a
a + b = 17 ----(2)
(1) + (2)
2a = 14
a = 7
By applying the value of a in (1), we get
7 - b = -3
-b = -3 - 7
-b = -10
b = 10
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