Words :
The product of a non zero real number and its reciprocal or multiplicative inverse is 1.
Numbers :
3 ⋅ (1/3) = (1/3) ⋅ 3 = 1
-7 ⋅ (-1/7) = (-1/7) ⋅ (-7) = 1
Algebra :
For any real number k (k ≠ 0),
k ⋅ (1/k) = (1/k) ⋅ k = 1
Note :
To divide by a number, you can multiply by its multiplicative inverse.
Problem 1 :
Verify whether 0.2 and 5 are multiplicative inverse to each other.
Solution :
If 0.2 and 5 are multiplicative inverse to each other, their product has to be 1.
0.2 x 5 = (1/5) x 5
= 1
Because the product is 1, 0.2 and 5 are multiplicative inverse to each other.
Problem 2 :
If a and b are multiplicative inverse to each other, find a in terms of b.
Solution :
Because a and b are multiplicative inverse to each other, their product is 1.
ab = 1
Solve for a : Divide each side by b.
a = 1/b
Problem 3 :
If (y + 5) and 1/7 are multiplicative inverse to each other, find the value of y.
Solution :
Because (y + 5) and 1/7 are multiplicative inverse to each other, their product is 1.
(y + 5) ⋅ 1/7 = 1
(y + 5) / 7 = 1
Multiply each side by 7.
y + 5 = 7
Subtract 5 from each side.
y = 2
Problem 4 :
If p + q = 5/2, p and q are multiplicative inverses, find the value of p.
Solution :
p + q = 5/2
Subtract p from each side.
q = 5/2 - p
q = 5/2 - 2p/2
q = (5 - 2p)/2
Because p and q are multiplicative inverses, their product is 1.
pq = 1
Substitute (5 - 2p)/2 for q.
p ⋅ (5 - 2p)/2 = 1
[p(5 - 2p)] / 2 = 1
Multiply each side by 2.
5p - 2p2 = 2
Subtract 2 from each side.
5p - 2p2 - 2 = 0
-2p2 + 5p - 2 = 0
Multiply each side by -1.
2p2 - 5p + 2 = 0
Solve for p by factoring.
2p2 - p - 4p + 2 = 0
p(2p - 1) - 2(2p - 1) = 0
(2p - 1)(p - 2) = 0
2p - 1 = 0 or p - 2 = 0
p = 1/2 or p = 2
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