If the product of two real numbers is 1, then they are reciprocals.
A number and its reciprocal are called multiplicative inverses.
For a real number 'y', its reciprocal '1/y' is its multiplicative inverse.
For '1/y', its reciprocal 'y' is its multiplicative inverse.
Problem 1 :
If x and y are multiplicative inverse to each other, find x in terms of y.
Solution :
Because x and y are multiplicative inverse to each other, their product is 1.
xy = 1
Solve for x : Divide each side by y.
x = 1/y
Problem 2 :
If (x + 3) and 1/5 are multiplicative inverse to each other, find the value of x.
Solution :
Because (x + 3) and 1/5 are multiplicative inverse to each other, their product is 1.
(x + 3) ⋅ 1/5 = 1
(x + 3) / 5 = 1
Multiply each side by 5.
x + 3 = 5
Subtract 3 from each side.
x = 2
Problem 3 :
If x + y = 10/3, x and y are multiplicative inverses, find the value of x.
Solution :
x + y = 10/3
Subtract x from each side.
y = 10/3 - x
y = 10/3 - 3x/3
y = (10 - 3x)/3
Because x and y are multiplicative inverses, their product is 1.
xy = 1
Substitute (10 - 3x)/3 for y.
x ⋅ (10 - 3x)/3 = 1
[x(10 - 3x)] / 3 = 1
Multiply each side by 3.
10x - 3x2 = 3
Subtract 3 from each side.
10x - 3x2 - 3 = 0
-3x2 + 10x - 3 = 0
Multiply each side by -1.
3x2 - 10x + 3 = 0
Solve for x by factoring.
3x2 - x - 9x + 3 = 0
x(3x - 1) - 3(3x - 1) = 0
(3x - 1)(x - 3) = 0
3x - 1 = 0 or x - 3 = 0
x = 1/3 or x = 3
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