Let OA = a vector , OB vector = b vector and q be the angle between a vector and b vector.
Draw BL perpendicular to OA. From the right triangle OLB
cos θ = OL/OB
OL = OB cos θ == |b| cos θ
But OL is the projection of b vector on a vector.
a vector . b vector = |a vector| |b vector| cosθ
= |a vector| OL
a vector . b vector = |a| (projection of b on a)
Question 1 :
Find the projection of the vector i vector + 3j vector + 7k vector on the vector 2i vector + 6j vector + 3k vector.
Solution :
a vector = (i + 3j + 7k) vector
b vector = (2i + 6j + 3k) vector
Projection of a vector on b vector = (a . b) / |b vector|
a vector . b vector = 1(2) + 3(6) + 7(3)
= 2 + 18 + 21
= 41
|b vector| = √(22 + 62 + 32) = √49 = 7
Projection of a vector on b vector = 41/7
Question 2 :
Find λ, when the projection of a = λ i + j + 4k on b = 2i + 6 j + 3k is 4 units.
Solution :
Projection of a vector on b vector = (a . b) / |b vector|
a = λ i + j + 4k on b = 2i + 6 j + 3k
a . b = λ(2) + 1(6) + 4(3) = 4
2λ + 6 + 12 = 4
2λ + 18 = 4
2λ = 4 - 18
2λ = -14
λ = -14/2 = -7
Hence the value of λ is -7.
Question 3 :
Three vectors a vector, b vector and c vector are such that |a vector|= 2, |b vector| = 3,|c vector| = 4 , and a vector + b vector + c vector = 0 . Find 4 a . b + 3b . c + 3c . a.
Solution :
a vector + b vector + c vector = 0
a vector + b vector = - c vector
|a vector + b vector| = |-c vector|
|a vector + b vector|2 = |-c vector|2
|avector|2+|bvector|2+ 2 a . b =|c vector|2
4 + 9 + 2 (a . b) = 16
13 + 2 (a . b) = 16
2 (a . b) = 16 - 13
2 (a . b) = 3
4 a . b = 6 -----(1)
||| ly
|a vector|2+|c vector|2+ 2 a . c =|b vector|2
4 + 16 + 2 (a . c) = 9
20 + 2 (a . c) = 9
2 (a . c) = 9 - 20
2 (a . c) = -11
a . c = -11/2
3 a . c = -33/2 -----(2)
||| ly
|b vector|2+|c vector|2+ 2 b . c =|a vector|2
9 + 16 + 2 (b . c) = 4
25 + 2 (b . c) = 4
2 (b . c) = 4 - 25
2 (b . c) = -21
b . c = -21/2
3 b . c = -63/2 -----(3)
4 a . b + 3 b . c + 3 c . a = 6 - (63/2) - (33/2)
= (12 - 63 - 33)/2
= (12 - 96)/2
= - 84/2
= -42
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